sin^2(2x)-3sin(2x)+1=0

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Solution for sin^2(2x)-3sin(2x)+1=0 equation:


Simplifying
sin2(2x) + -3sin(2x) + 1 = 0

Remove parenthesis around (2x)
in2s * 2x + -3sin(2x) + 1 = 0

Reorder the terms for easier multiplication:
2in2s * x + -3sin(2x) + 1 = 0

Multiply in2s * x
2in2sx + -3sin(2x) + 1 = 0

Remove parenthesis around (2x)
2in2sx + -3ins * 2x + 1 = 0

Reorder the terms for easier multiplication:
2in2sx + -3 * 2ins * x + 1 = 0

Multiply -3 * 2
2in2sx + -6ins * x + 1 = 0

Multiply ins * x
2in2sx + -6insx + 1 = 0

Reorder the terms:
1 + -6insx + 2in2sx = 0

Solving
1 + -6insx + 2in2sx = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -6insx + -1 + 2in2sx = 0 + -1

Reorder the terms:
1 + -1 + -6insx + 2in2sx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -6insx + 2in2sx = 0 + -1
-6insx + 2in2sx = 0 + -1

Combine like terms: 0 + -1 = -1
-6insx + 2in2sx = -1

Reorder the terms:
1 + -6insx + 2in2sx = -1 + 1

Combine like terms: -1 + 1 = 0
1 + -6insx + 2in2sx = 0

The solution to this equation could not be determined.

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